Identifying and Correcting Errors (Unit 1.4)

Become familiar with types of errors and strategies to fixing them

Lightly Review Videos and take notes on topics with Blog

Complete assigned MCQ questions

Here are some code segments you can practice fixing:

alphabet = "abcdefghijklmnopqrstuvwxyz"

alphabetList = []

for i in alphabet:
    alphabetList.append(i)

print(alphabetList)

['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

The intended outcome is to determine where the letter is in the alphabet using a while loop

There are two changes you can make

letter = input("What letter would you like to check?")

i = 0

while i < 26:
    if alphabetList[i] == letter:
        print("The letter " + letter + " is the " + str(i+1) + " letter in the alphabet")
    i += 1

The letter z is the 26 letter in the alphabet

letter = input("What letter would you like to check?")

count = 0

for i in alphabetList:
    if i == letter:
        print("The letter " + letter + " is the " + str(count+1) + " letter in the alphabet")
    count += 1

The letter z is the 26 letter in the alphabet

evens = []
i = 0

while i <= 10:
    evens.append(numbers[i])
    i += 2

print(evens)

This code should output the odd numbers from 0 - 10 using a while loop.

evens = []
i = 0

while i <= 10:
    evens.append(i)
    i += 2

print(evens)

[0, 2, 4, 6, 8, 10]

numbers = [0,1,2,3,4,5,6,7,8,9,10]
evens = []

for i in numbers:
    if (numbers[i] % 2 == 0):
        evens.append(numbers[i])

print(evens)

[0, 2, 4, 6, 8, 10]

This code should output the odd numbers from 0 - 10 using a for loop.

numbers = [0,1,2,3,4,5,6,7,8,9,10]
odds = []

for i in numbers:
    if (numbers[i] % 2 == 1):
        odds.append(numbers[i])

print(odds)

[1, 3, 5, 7, 9]

The intended outcome is printing a number between 1 and 100 once, if it is a multiple of 2 or 5

3 changes to the code will give the expected outcome.

numbers = []
newNumbers = []
i = 0

while i < 101:
    numbers.append(i)
    i += 1

for i in numbers:
    if numbers[i] % 10 == 5:
        newNumbers.append(numbers[i])
    if numbers[i] % 2 == 0:
        newNumbers.append(numbers[i])

print(newNumbers)

[0, 2, 4, 5, 6, 8, 10, 12, 14, 15, 16, 18, 20, 22, 24, 25, 26, 28, 30, 32, 34, 35, 36, 38, 40, 42, 44, 45, 46, 48, 50, 52, 54, 55, 56, 58, 60, 62, 64, 65, 66, 68, 70, 72, 74, 75, 76, 78, 80, 82, 84, 85, 86, 88, 90, 92, 94, 95, 96, 98, 100]

menu =  {"burger": 3.99, 
         "fries": 1.99,
         "drink": 0.99} # use of dictionary
total = 0

#shows the user the menu and prompts them to select an item
print("Saavan Gade Restaurant Menu")
for k,v in menu.items(): # "k" is the item name, "v" is the price. "k" stands for key and "v" stands for value.
    print(k + "  $" + str(v)) #why does v have "str" in front of it?

#ideally the code should prompt the user multiple times
print("Please select items from the menu.Type 'done' when finished")
item = input("Please select items from the menu.Type 'done' when finished")

while True:             # Loop continuously
    inp = input()       # Get the input
    if inp == "burger": # input for burger
        print("1 burger: $3.99") 
        total = total + 3.99
    elif inp == "fries": # input for fries
        print("1 fries: $1.99")   
        total = total + 1.99
    elif inp == "drink": # input for a drink
         print("1 drink: $0.99")
         total = total + 0.99
    elif inp == "done": # input for completing the order
        break # stop asking the user for inputs

# print the total order cost
print("Your total is $" + str(total))

Saavan Gade Restaurant Menu
burger  $3.99
fries  $1.99
drink  $0.99
Please select items from the menu.Type 'done' when finished
1 fries: $1.99
1 burger: $3.99
Your total is $5.98